任务1
源代码
T.h
#pragma once#include <string>// 类T: 声明 class T { // 对象属性、方法 public:T(int x = 0, int y = 0); // 普通构造函数T(const T &t); // 复制构造函数T(T &&t); // 移动构造函数~T(); // 析构函数void adjust(int ratio); // 按系数成倍调整数据void display() const; // 以(m1, m2)形式显示T类对象信息private:int m1, m2;// 类属性、方法 public:static int get_cnt(); // 显示当前T类对象总数public:static const std::string doc; // 类T的描述信息static const int max_cnt; // 类T对象上限private:static int cnt; // 当前T类对象数目// 类T友元函数声明friend void func(); };// 普通函数声明 void func();
T,cpp
#include "T.h" #include <iostream> #include <string>// 类T实现// static成员数据类外初始化 const std::string T::doc{"a simple class sample"}; const int T::max_cnt = 999; int T::cnt = 0;// 类方法 int T::get_cnt() {return cnt; }// 对象方法 T::T(int x, int y): m1{x}, m2{y} { ++cnt; std::cout << "T constructor called.\n"; } T::T(const T &t): m1{t.m1}, m2{t.m2} {++cnt;std::cout << "T copy constructor called.\n"; }T::T(T &&t): m1{t.m1}, m2{t.m2} {++cnt;std::cout << "T move constructor called.\n"; } T::~T() {--cnt;std::cout << "T destructor called.\n"; } void T::adjust(int ratio) {m1 *= ratio;m2 *= ratio; } void T::display() const {std::cout << "(" << m1 << ", " << m2 << ")" ; } // 普通函数实现 void func() {T t5(42);t5.m2 = 2049;std::cout << "t5 = "; t5.display(); std::cout << '\n'; }
task1.cpp
#include "T.h" #include <iostream>void test_T();int main() {std::cout << "test Class T: \n";test_T();std::cout << "\ntest friend func: \n";func(); }void test_T() {using std::cout;using std::endl;cout << "T info: " << T::doc << endl;cout << "T objects'max count: " << T::max_cnt << endl;cout << "T objects'current count: " << T::get_cnt() << endl << endl;T t1;cout << "t1 = "; t1.display(); cout << endl;T t2(3, 4);cout << "t2 = "; t2.display(); cout << endl;T t3(t2);t3.adjust(2);cout << "t3 = "; t3.display(); cout << endl;T t4(std::move(t2));cout << "t4 = "; t4.display(); cout << endl;cout << "test: T objects'current count: " << T::get_cnt() << endl; }
运行结果截图

问题1
不能,友元函数的声明需满足 “先声明,后使用”。在类内部声明func为友元时,编译器需要知道func的函数原型。若删除类外部的void func();声明,类内部的友元声明会因找不到func的完整原型而报错。

问题2
普通构造函数功能:初始化对象的成员变量(如x、y),是对象创建时的默认初始化方式。调用时机:当使用T t;(默认参数)或T t(3,4);(显式传参)创建对象时调用。
复制构造函数功能:用一个已存在的对象t初始化新对象,复制t的成员变量值到新对象。调用时机:当对象被复制时(如T t2 = t1;、函数参数按值传递对象、函数返回对象时)调用。
移动构造函数功能:“窃取” 临时对象(右值)的资源,避免不必要的复制,提高效率。调用时机:当用临时对象(如函数返回的匿名对象)初始化新对象时调用。
析构函数功能:释放对象占用的资源(如动态内存、文件句柄等),完成对象销毁前的清理工作。调用时机:当对象生命周期结束时(如局部对象出作用域、动态分配的对象被delete时)自动调用。
问题3
不能
C++ 中,类的静态成员的定义只能出现一次。若将其剪切到T.h中,当T.h被多个源文件包含时,会导致静态成员在多个目标文件中被重复定义,链接阶段会报错提示 “multiple definition of T::doc”
任务2
源代码
complex.h
#ifndef COMPLEX_H #define COMPLEX_H#include <string>class Complex { public:static const std::string doc;Complex();Complex(double real);Complex(double real, double imag);Complex(const Complex& other);double get_real() const;double get_imag() const;void add(const Complex& other);friend void output(const Complex& c);friend double abs(const Complex& c);friend Complex add(const Complex& a, const Complex& b);friend bool is_equal(const Complex& a, const Complex& b);friend bool is_not_equal(const Complex& a, const Complex& b);private:double real;double imag; };#endif
complex.cpp
#include "Complex.h" #include <iostream> #include <cmath> const std::string Complex::doc = "a simplified complex class"; Complex::Complex() : real(0.0), imag(0.0) {} Complex::Complex(double real) : real(real), imag(0.0) {} Complex::Complex(double real, double imag) : real(real), imag(imag) {} Complex::Complex(const Complex& other) : real(other.real), imag(other.imag) {}double Complex::get_real() const {return real; }double Complex::get_imag() const {return imag; }void Complex::add(const Complex& other) {real += other.real;imag += other.imag; }void output(const Complex& c) {if (c.imag >= 0) {std::cout << c.real << " + " << c.imag << "i";} else {std::cout << c.real << " - " << -c.imag << "i"; } } double abs(const Complex& c) {// 复数模长公式:sqrt(real2 + imag2)return std::sqrt(c.real * c.real + c.imag * c.imag); } Complex add(const Complex& a, const Complex& b) {// 返回两复数相加的结果(新对象)return Complex(a.real + b.real, a.imag + b.imag); } bool is_equal(const Complex& a, const Complex& b) {return (a.real == b.real) && (a.imag == b.imag); } bool is_not_equal(const Complex& a, const Complex& b) {return !is_equal(a, b); }
task2.cpp
#include "Complex.h" #include <iostream> #include <iomanip> #include <complex>void test_Complex(); void test_std_complex();int main() {std::cout << "*******测试1: 自定义类Complex*******\n";test_Complex();std::cout << "\n*******测试2: 标准库模板类complex*******\n";test_std_complex(); }void test_Complex() {using std::cout;using std::endl;using std::boolalpha;cout << "类成员测试: " << endl;cout << Complex::doc << endl << endl;cout << "Complex对象测试: " << endl;Complex c1;Complex c2(3, -4);Complex c3(c2);Complex c4 = c2;const Complex c5(3.5);cout << "c1 = "; output(c1); cout << endl;cout << "c2 = "; output(c2); cout << endl;cout << "c3 = "; output(c3); cout << endl;cout << "c4 = "; output(c4); cout << endl;cout << "c5.real = " << c5.get_real() << ", c5.imag = " << c5.get_imag() << endl << endl;cout << "复数运算测试: " << endl;cout << "abs(c2) = " << abs(c2) << endl;c1.add(c2);cout << "c1 += c2, c1 = "; output(c1); cout << endl;cout << boolalpha;cout << "c1 == c2 : " << is_equal(c1, c2) << endl;cout << "c1 != c2 : " << is_not_equal(c1, c2) << endl;c4 = add(c2, c3);cout << "c4 = c2 + c3, c4 = "; output(c4); cout << endl; }void test_std_complex() {using std::cout;using std::endl;using std::boolalpha;cout << "std::complex<double>对象测试: " << endl;std::complex<double> c1;std::complex<double> c2(3, -4);std::complex<double> c3(c2);std::complex<double> c4 = c2;const std::complex<double> c5(3.5);cout << "c1 = " << c1 << endl;cout << "c2 = " << c2 << endl;cout << "c3 = " << c3 << endl;cout << "c4 = " << c4 << endl;cout << "c5.real = " << c5.real() << ", c5.imag = " << c5.imag() << endl << endl;cout << "复数运算测试: " << endl;cout << "abs(c2) = " << abs(c2) << endl;c1 += c2;cout << "c1 += c2, c1 = " << c1 << endl;cout << boolalpha;cout << "c1 == c2 : " << (c1 == c2)<< endl;cout << "c1 != c2 : " << (c1 != c2) << endl;c4 = c2 + c3;cout << "c4 = c2 + c3, c4 = " << c4 << endl; }
运行结果截图


问题1
标准库模板类std::complex更简洁。
Complex需通过成员函数(add)或全局函数实现。output需要访问私有成员real和imag以格式化输出;abs需要计算real和imag的平方和;add需要获取两个复数的real和imag才能计算和。这些函数必须访问私有数据,因此需要声明为友元。std::abs对于std::complex的重载是全局函数,通过complex的公有成员函数(如real()、imag())获取实部和虚部,而非通过友元访问私有数据。friend:PlayerControl.h
#pragma once #include <string>enum class ControlType {Play, Pause, Next, Prev, Stop, Unknown};class PlayerControl { public:PlayerControl();ControlType parse(const std::string& control_str); // 实现std::string --> ControlType转换void execute(ControlType cmd) const; // 执行控制操作(以打印输出模拟) static int get_cnt();private:static int total_cnt; };
PlayerControl.cpp
#include "PlayerControl.h" #include <string> #include <iostream> int PlayerControl::total_cnt = 0;PlayerControl::PlayerControl() {}ControlType PlayerControl::parse(const std::string& control_str) {// 将输入字符串转换为小写std::string lower_str;for (char c : control_str) {lower_str += static_cast<char>(tolower(c));}// 匹配转换后的字符串并返回对应的枚举值if (lower_str == "play") {total_cnt++;return ControlType::Play;} else if (lower_str == "pause") {total_cnt++;return ControlType::Pause;} else if (lower_str == "next") {total_cnt++;return ControlType::Next;} else if (lower_str == "prev") {total_cnt++;return ControlType::Prev;} else if (lower_str == "stop") {total_cnt++;return ControlType::Stop;} else {total_cnt++;return ControlType::Unknown;} }void PlayerControl::execute(ControlType cmd) const {switch (cmd) {case ControlType::Play:std::cout << "[play] Playing music...\n";break;case ControlType::Pause:std::cout << "[Pause] Music paused\n";break;case ControlType::Next:std::cout << "[Next] Skipping to next track\n";break;case ControlType::Prev:std::cout << "[Prev] Back to previous track\n";break;case ControlType::Stop:std::cout << "[Stop] Music stopped\n";break;default:std::cout << "[Error] unknown control\n";break;} }int PlayerControl::get_cnt() {return total_cnt; }
task3.cpp
#include "PlayerControl.h" #include <iostream>void test() {PlayerControl controller;std::string control_str;std::cout << "Enter Control: (play/pause/next/prev/stop/quit):\n";while(std::cin >> control_str) {if(control_str == "quit")break;ControlType cmd = controller.parse(control_str);controller.execute(cmd);std::cout << "Current Player control: " << PlayerControl::get_cnt() << "\n\n";} }int main() {test(); }
#ifndef FRACTION_H #define FRACTION_H#include <string>class Fraction { public:static const std::string doc; Fraction(int up = 0);Fraction(int up, int down);Fraction(const Fraction& other);int get_up() const;int get_down() const;Fraction negative() const;private:int up_; int down_; void simplify();static int gcd(int a, int b); };namespace FractionUtil {void output(const Fraction& f);Fraction add(const Fraction& f1, const Fraction& f2);Fraction sub(const Fraction& f1, const Fraction& f2);Fraction mul(const Fraction& f1, const Fraction& f2);Fraction div(const Fraction& f1, const Fraction& f2); }using namespace FractionUtil; #endif // FRACTION_H
Fraction.cpp
#include "Fraction.h" #include <stdexcept> #include <iostream> #include <cmath>const std::string Fraction::doc = "Fraction类 v 0.01版.\n目前仅支持分数对象的构造、输出、加/减/乘/除运算.";int Fraction::gcd(int a, int b) {a = std::abs(a);b = std::abs(b);while (b != 0) {int temp = b;b = a % b;a = temp;}return a; }void Fraction::simplify() {if (down_ == 0) {throw std::invalid_argument("分母不能为0");}if (down_ < 0) {up_ *= -1;down_ *= -1;}int common = gcd(up_, down_);if (common != 0) {up_ /= common;down_ /= common;} } Fraction::Fraction(int up) : up_(up), down_(1) {simplify(); }Fraction::Fraction(int up, int down) : up_(up), down_(down) {simplify(); }Fraction::Fraction(const Fraction& other) : up_(other.up_), down_(other.down_) {} int Fraction::get_up() const {return up_; }int Fraction::get_down() const {return down_; }Fraction Fraction::negative() const {return Fraction(-up_, down_); } namespace FractionUtil {void output(const Fraction& f) {std::cout << f.get_up() << "/" << f.get_down();}Fraction add(const Fraction& f1, const Fraction& f2) {int new_up = f1.get_up() * f2.get_down() + f2.get_up() * f1.get_down();int new_down = f1.get_down() * f2.get_down();return Fraction(new_up, new_down);}Fraction sub(const Fraction& f1, const Fraction& f2) {int new_up = f1.get_up() * f2.get_down() - f2.get_up() * f1.get_down();int new_down = f1.get_down() * f2.get_down();return Fraction(new_up, new_down);}Fraction mul(const Fraction& f1, const Fraction& f2) {int new_up = f1.get_up() * f2.get_up();int new_down = f1.get_down() * f2.get_down();return Fraction(new_up, new_down);}Fraction div(const Fraction& f1, const Fraction& f2) {if (f2.get_up() == 0) {throw std::invalid_argument("除数不能为0");}int new_up = f1.get_up() * f2.get_down();int new_down = f1.get_down() * f2.get_up();return Fraction(new_up, new_down);} }
task4.cpp
#include "Fraction.h" #include <iostream>void test1(); void test2();int main() {std::cout << "测试1: Fraction类基础功能测试\n";test1();std::cout << "\n测试2: 分母为0测试: \n";test2(); }void test1() {using std::cout;using std::endl; cout << "Fraction类测试: " << endl;cout << Fraction::doc << endl << endl;Fraction f1(5);Fraction f2(3, -4), f3(-18, 12);Fraction f4(f3);cout << "f1 = "; output(f1); cout << endl;cout << "f2 = "; output(f2); cout << endl;cout << "f3 = "; output(f3); cout << endl;cout << "f4 = "; output(f4); cout << endl;const Fraction f5(f4.negative());cout << "f5 = "; output(f5); cout << endl;cout << "f5.get_up() = " << f5.get_up() << ", f5.get_down() = " << f5.get_down() << endl;cout << "f1 + f2 = "; output(add(f1, f2)); cout << endl;cout << "f1 - f2 = "; output(sub(f1, f2)); cout << endl;cout << "f1 * f2 = "; output(mul(f1, f2)); cout << endl;cout << "f1 / f2 = "; output(div(f1, f2)); cout << endl;cout << "f4 + f5 = "; output(add(f4, f5)); cout << endl; }void test2() {using std::cout;using std::endl;Fraction f6(42, 55), f7(0, 3);cout << "f6 = "; output(f6); cout << endl;cout << "f7 = "; output(f7); cout << endl;cout << "f6 / f7 = "; output(div(f6, f7)); cout << endl; }
问题