Camping Groups
我们先计算出， 每个点当leader所能掌控的最多人数。 然后我们把询问离线， 丢到responsibility最大的那个地方去。
然后从大到小往线段树里加人， 加入完之后处理掉当前的询问。
如果强制在线的话就只能树套树啦。
#include<bits/stdc++.h> #define LL long long #define LD long double #define ull unsigned long long #define fi first #define se second #define mk make_pair #define PLL pair<LL, LL> #define PLI pair<LL, int> #define PII pair<int, int> #define SZ(x) ((int)x.size()) #define ALL(x) (x).begin(), (x).end() #define fio ios::sync_with_stdio(false); cin.tie(0);using namespace std;const int N = 1e5 + 7; const int inf = 0x3f3f3f3f; const LL INF = 0x3f3f3f3f3f3f3f3f; const int mod = 1e9 + 7; const double eps = 1e-8; const double PI = acos(-1);template<class T, class S> inline void add(T& a, S b) {a += b; if(a >= mod) a -= mod;} template<class T, class S> inline void sub(T& a, S b) {a -= b; if(a < 0) a += mod;} template<class T, class S> inline bool chkmax(T& a, S b) {return a < b ? a = b, true : false;} template<class T, class S> inline bool chkmin(T& a, S b) {return a > b ? a = b, true : false;}int n, k, q; int a[N], r[N]; int c[N];int hsa[N], tota; int hsr[N], totr;int ans[N];vector<PII> vc[N]; vector<pair<PII, int>> qus[N];struct Bit {int a[N];void modify(int x, int v) {for(int i = x; i < N; i += i & -i) a[i] += v;}int sum(int x) {int ans = 0;for(int i = x; i; i -= i & -i) ans += a[i];return ans;}int query(int L, int R) {if(L > R) return 0;return sum(R) - sum(L - 1);} } bit;struct SegmentTree { #define lson l, mid, rt << 1 #define rson mid + 1, r, rt << 1 | 1int mx[N << 2];inline void pull(int rt) {mx[rt] = max(mx[rt << 1], mx[rt << 1 | 1]);}void update(int L, int R, int val, int l, int r, int rt) {if(R < l || r < L || R < L) return;if(L <= l && r <= R) {chkmax(mx[rt], val);return;}int mid = l + r >> 1;update(L, R, val, lson);update(L, R, val, rson);pull(rt);}int query(int L, int R, int l, int r, int rt) {if(R < l || r < L || R < L) return 0;if(L <= l && r <= R) return mx[rt];int mid = l + r >> 1;return max(query(L, R, lson), query(L, R, rson));} } Tree;int getPosa(int x) {return lower_bound(hsa + 1, hsa + 1 + tota, x) - hsa; } int getPosr(int x) {return lower_bound(hsr + 1, hsr + 1 + totr, x) - hsr; }int main() {memset(ans, -1, sizeof(ans));scanf("%d%d", &n, &k);for(int i = 1; i <= n; i++) scanf("%d", &a[i]), hsa[++tota] = a[i];for(int i = 1; i <= n; i++) scanf("%d", &r[i]), hsr[++totr] = r[i];sort(hsa + 1, hsa + 1 + tota); tota = unique(hsa + 1, hsa + 1 + tota) - hsa - 1;sort(hsr + 1, hsr + 1 + totr); totr = unique(hsr + 1, hsr + 1 + totr) - hsr - 1;for(int i = 1; i <= n; i++) {vc[lower_bound(hsa + 1, hsa + 1 + tota, a[i]) - hsa].push_back(mk(r[i], 0));}for(int i = 1; i <= tota; i++) {for(auto& t : vc[i]) bit.modify(getPosr(t.fi), 1);for(auto& t : vc[i]) {t.se = bit.query(getPosr(t.fi - k), getPosr(t.fi + k + 1) - 1);}}scanf("%d", &q);for(int i = 1; i <= q; i++) {int x, y; scanf("%d%d", &x, &y);int maxa = max(a[x], a[y]);if(r[x] > r[y]) swap(x, y);qus[lower_bound(hsa + 1, hsa + 1 + tota, maxa) - hsa].push_back(mk(mk(r[y] - k, r[x] + k), i));}for(int i = tota; i >= 1; i--) {for(auto& t : vc[i]) Tree.update(getPosr(t.fi), getPosr(t.fi), t.se, 1, totr, 1);for(auto& q : qus[i]) ans[q.se] = Tree.query(getPosr(q.fi.fi), getPosr(q.fi.se + 1) - 1, 1, totr, 1);}for(int i = 1; i <= q; i++) printf("%d\n", ans[i] == 0 ? -1 : ans[i]);return 0; }/* */
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