题目描述:
笨小猴的词汇量很小,所以每次做英语选择题的时候都很头疼。但是他找到了一种方法,经试验证明,用这种方法去选择选项的时候选对的几率非常大!
这种方法的具体描述如下:假设maxn是单词中出现次数最多的字母的出现次数,minn是单词中出现次数最少的字母的出现次数,如果maxn-minn是一个质数,那么笨小猴就认为这是个Lucky Word,这样的单词很可能就是正确的答案。
代码:
package lanqiao;import java.math.BigInteger;
import java.util.*;public class Main {public static void main(String[] args) {Scanner sc = new Scanner(System.in);String a = sc.next();int maxn = 0;int minn = 100;int x = 0;int sum = 0;for (int i = 0; i < a.length(); i++) {for (int j = 0; j < a.length(); j++) {if (a.charAt(i)==a.charAt(j)){x++;}}if (x>maxn){maxn = x;}if (x<minn){minn = x;}x = 0;}sum = maxn-minn;int n = 0;for (int i = 1; i <= sum; i++) {if (sum%i==0){n++;}}if (n==2){System.out.println("Lucky Word");System.out.println(sum);}else {System.out.println("No Answer");System.out.println("0");}}
}