mysql列题
- 1.查询学过「张三」老师授课的同学的信息
- 2.查询没有学全所有课程的同学的信息
- 3.查询没学过"张三"老师讲授的任一门课程的学生姓名
- 4.查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩
- 5.检索" 01 "课程分数小于 60,按分数降序排列的学生信息
- 6.按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
- 7.查询各科成绩最高分、最低分和平均分:
1.查询学过「张三」老师授课的同学的信息
select s.*,sc.cid,c.cname,sc.score,t.tname from t_mysql_teacher t,
 t_mysql_course c,
 t_mysql_score sc,
 t_mysql_student s
 where t.tid=c.tid
 and c.cid=sc.cid and sc.sid=s.sid and t.tname =‘张三’
2.查询没有学全所有课程的同学的信息
SELECT
 s.sid,
 s.sname, count( sc.score ) n
 FROM
 t_mysql_student s,
 t_mysql_score sc
 WHERE
 s.sid = sc.sid
 GROUP BY
 s.sid,
 s.sname
 HAVING
 n < ( SELECT count( 1 ) FROM t_mysql_course )
3.查询没学过"张三"老师讲授的任一门课程的学生姓名
select * from t_mysql_student where sid not in(
 select sc.sid from t_mysql_teacher t,
 t_mysql_course c,
 t_mysql_score sc,
 t_mysql_student s
 where t.tid=c.tid
 and c.cid=sc.cid and sc.sid=s.sid and t.tname =‘张三’
 )
4.查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩
SELECT
 s.sid,
 s.sname,
 count( sc.score ) n,
 round( avg( sc.score ), 2 )
 FROM
 t_mysql_score sc,
 t_mysql_student s
 WHERE
 sc.sid = s.sid
 AND sc.score < 60 GROUP BY s.sid, s.sname HAVING n >= 2
5.检索" 01 "课程分数小于 60,按分数降序排列的学生信息
SELECT
 s.*,
 sc.score from
 t_mysql_score sc,
 t_mysql_student s
 WHERE
 sc.sid = s.sid
 AND sc.score < 60
 AND sc.cid = ‘01’
 ORDER BY
 sc.score DESC
6.按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
SELECT
 s.sid ,s.sname,
 round( avg( sc.score ), 2 ) avg,
 min( CASE WHEN sc.cid = ‘01’ THEN sc.score END ) 语文,
 min( CASE WHEN sc.cid = ‘02’ THEN sc.score END ) 数学,
 min( CASE WHEN sc.cid = ‘03’ THEN sc.score END ) 英语
FROM
 t_mysql_student s,
 t_mysql_score sc
 WHERE
 s.sid = sc.sid
 GROUP BY
 s.sid,
 s.sname
 ORDER BY
 avg DESC;
7.查询各科成绩最高分、最低分和平均分:
以如下形式显示:课程 ID,课程 name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90
 要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列
SELECT
 c.cid,
 c.cname,
 max( sc.score ) 最高分,
 min( 最低分 ),
 round( avg( sc.score ) ) 平均分,
 CONCAT(
 ROUND(
 sum( IF ( sc.score >= 60, 1, 0 ) / count( sc.score ) * 100, 2 ),
 ‘%’
 ) 及格率,
 CONCAT(
 ROUND(
 sum(
 IF
 ( sc.score >= 70 AND sc.score < 80, 1, 0 ) / count( sc.score ) * 100,
 2
 ),
 ‘%’
 ) 中等率,
 CONCAT(
 ROUND(
 sum(
 IF
 ( sc.score >= 80 AND sc.score < 90, 1, 0 ) / count( sc.score ) * 100,
 2
 ),
 ‘%’
 ) 优良率,
 CONCAT(
 ROUND(
 sum( IF ( sc.score >= 90, 1, 0 ) / count( sc.score ) * 100, 2 ),
 ‘%’
 ) 优秀率
 FROM
 t_mysql_score sc,
 t_mysql_course c,
 t_mysql_student s,
WHERE
 sc.cid = c.cid
 AND sc.sid = s.sid
 GROUP BY
 c.cid c.cname
from t_mysql_score sc,
 t_mysql_course c,
 t_mysql_student s
 where sc.cid=c.cid
 and sc.sid =s.sid
 GROUP BY
 c.cid,
 c.cname
在这里插入图片描述