题意:每一条边至少有一个端点要涂颜色,问最少涂几个点
思路:最小顶点覆盖:用最少的点,让每条边都至少和其中一个点关联,显然是道裸最小顶点覆盖题;
参考:二分图
代码:
#include<iostream> #include<algorithm> #include<cstdio> #include<stdio.h> #include<string.h> #include<queue> #include<cmath> #include<map> #include<set> #include<vector> using namespace std; typedef unsigned long long ull; const int maxn = 500 + 10; const ull seed = 131; struct Edge{int v, next; }edge[maxn * maxn * 2]; int head[maxn], match[maxn], vis[maxn], tot; void addEdge(int u, int v){edge[tot].v = v;edge[tot].next = head[u];head[u] = tot++; } bool dfs(int u){for(int i = head[u]; i != -1; i = edge[i].next){int v = edge[i].v;if(!vis[v]){vis[v] = 1;if(match[v] == -1 || dfs(match[v])){match[v] = u;match[u] = v;return true;}}}return false; } int solve(int n){int ans = 0;memset(match, -1, sizeof(match));for(int i = 1; i <= n; i++){if(match[i] == -1){memset(vis, 0, sizeof(vis));if(dfs(i)) ans++;}}return ans; } int main(){int n, m;while(~scanf("%d%d", &n, &m)){memset(head, -1, sizeof(head));tot = 0;for(int i = 1; i <= m; i++){int u, v;scanf("%d%d", &u, &v);addEdge(u, v);addEdge(v, u);}printf("%d\n", solve(n));}return 0; }