1 题目

剑指offer之求两个数之和(不能使用四则运算)

 

 

 

 

 

 

 

 

2 代码实现

#include<stdio.h>int add(int num1, int num2)
{int sum1;int carry;do{sum1 = (num1 ^ num2);carry = (num1 & num2) << 1;num1 = sum1;num2 = carry;} while (carry != 0);return num1;
}int main()
{int result = add(3, 5);printf("result is %d\n", result);return 0;
}

 

 

 

3 运行结果

result is 8