package com.lixuan.houhou;
public class SxisuArray {
public static void main(String[] args) {
//稀疏数组 :创建一个二维数组11*11 0：没有棋子 1：黑棋 2：白棋
int[][] array1 = new int[11][11];
array1[1][2] = 1;
array1[2][3] = 2;
//输出原始的数组
System.out.println("输出原始数组");
for (int[] ints : array1) {for (int anInt : ints) {System.out.print(anInt + "\t");}System.out.println("\n");}//转换为稀疏数组保存//1.获取有效值的个数int sum = 0;for (int i = 0; i < array1.length; i++) {for (int j = 0; j < array1[i].length; j++) {if (array1[i][j] != 0) {sum++;}}}System.out.println("有效值个数为" + sum);//2.创建一个稀疏数组的数组int[][] array2 = new int[sum + 1][3];array2[0][0] = 11;array2[0][1] = 11;array2[0][2] = sum;//遍历上面array二维数组，将非0的值存放稀疏数组中int count = 0;for (int i = 0; i < array1.length; i++) {for (int j = 0; j < array1[i].length; j++) {if (array1[i][j] != 0) {count++;array2[count][0] = i;array2[count][1] = j;array2[count][2] = array1[i][j];}}}//输出稀疏数组System.out.println("稀疏数组");for (int i = 0; i < array2.length; i++) {System.out.println(array2[i][0] + "\t" + array2[i][1] + "\t" + array2[i][2] + "\t");}//还原稀疏数组//读取保存稀疏数组中特殊值int[][] array3 = new int[array2[0][0]][array2[0][1]];//给其他非特殊元素还原值for (int i = 1; i < array2.length; i++) {array3[array2[i][0]][array2[i][1]] = array2[i][2];}//打印还原数组array3for (int[] ints : array3) {for (int anInt : ints) {System.out.print(anInt + "\t");}System.out.println("\n");}}
}
)
