家长班：

public class Person {

String firstName;

String lastName;

Long id;

List phoneNumber = new ArrayList<>();

int age;

public Person(String firstName, String lastName, int age, Long id, List phone) {

super();

this.firstName = firstName;

this.lastName = lastName;

this.age = age;

this.id = id;

this.phoneNumber = phone;

}

儿童电话对象(第1级)：

public class Phone {

String number;

String type;

Long id;

public Phone(String number, String type, Long id) {

super();

this.number = number;

this.type = type;

this.id = id;

}

}

我正在尝试获取其电话对象类型为home且其编号应包含“888”的person对象.

List list = personList.stream().map(p -> p.getPhoneNumber().stream()).

flatMap(inputStream -> inputStream).filter(p -> p.number.contains("888") && p.type.equals("HOME")).collect(Collectors.toList());

System.out.println(list.toString());

从上面的流代码,我能够获得电话对象.但是如何在同一个函数中获取该手机对象的父对象呢？

我试过这种方式,我为非匹配的对象获取null.

List finalList = personList.stream().map( per -> {

List phones = per.getPhoneNumber();

Optional ph = phones.stream().filter(p -> p.number.contains("888") && p.type.equals("HOME")).findAny();

if(ph.isPresent())

return per;

return null;

}).collect(Collectors.toList());