位运算使奇数+1 偶数-1_C ++程序打印从1到N的所有偶数和奇数

位运算使奇数+1 偶数-1

Problem: Take input from the user (N) and print all EVEN and ODD numbers between 1 to N.

问题：从用户那里输入(N)，并打印1至N之间的所有偶数和奇数编号。

Solution:

解：

Input an integer number (N).
输入一个整数( N )。
Run two separate loops from 1 to N.
从1到N运行两个单独的循环。
In the first loop, check the condition to check EVEN numbers and print them.
在第一个循环中，检查条件以检查偶数并打印它们。
In the second loop, check the condition to check ODD numbers and print them.
在第二个循环中，检查条件以检查奇数编号并打印它们。
To check EVEN/ODD number – find the remainder dividing by 2, if it is 0 then the number will be an EVEN number, else the number will be an ODD number.
要检查EVEN / ODD号码-找到除以2的余数，如果为0，则该号码将为EVEN号码，否则该号码将为ODD号码。

C++ program:

C ++程序：

// C++ program to print all
// Even and Odd numbers from 1 to N
#include <iostream>
using namespace std;
// function : evenNumbers
// description: to print EVEN numbers only.
void evenNumbers(int n)
{
int i;
for (i = 1; i <= n; i++) {
//condition to check EVEN numbers
if (i % 2 == 0)
cout << i << " ";
}
cout << "\n";
}
// function : oddNumbers
// description: to print ODD numbers only.
void oddNumbers(int n)
{
int i;
for (i = 1; i <= n; i++) {
//condition to check ODD numbers
if (i % 2 != 0)
cout << i << " ";
}
cout << "\n";
}
// main code
int main()
{
int N;
// input the value of N
cout << "Enter the value of N (limit): ";
cin >> N;
cout << "EVEN numbers are...\n";
evenNumbers(N);
cout << "ODD numbers are...\n";
oddNumbers(N);
return 0;
}

Output

输出量

RUN 1:
Enter the value of N (limit): 11
EVEN numbers are...
2 4 6 8 10
ODD numbers are...
1 3 5 7 9 11
RUN 2:
Enter the value of N (limit): 50
EVEN numbers are...
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50
ODD numbers are...
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49