1065 A+B and C (64bit) (20 分)
Given three integers A, B and C in [−2
​63
​​ ,2
​63
​​ ], you are supposed to tell whether A+B>C.

Input Specification:
The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:
For each test case, output in one line Case #X: true if A+B>C, or Case #X: false otherwise, where X is the case number (starting from 1).

Sample Input:
3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0
Sample Output:
Case #1: false
Case #2: true
Case #3: false

#include <iostream>
using namespace std;
int main()
{int t;cin >> t;for (int i = 1; i <= t; i++){long long a, b, c,sum;scanf("%lld%lld%lld", &a, &b, &c);//这里不能用cin，知道为什么的告诉我一声。很迷cout << "Case #" << i << ": ";sum = a + b;if (a > 0 && b > 0 && sum < 0)cout << "true";else if (a < 0 && b < 0 && sum >= 0)cout << "false";else if (sum > c)cout << "true";elsecout << "false";cout<<endl;}return 0;
}