法一

public class Methodfifth {

public void mixed(int array1[], int n1, int array2[], int n2)

{

int i = 0, j = 0,number=0;

while (i < n1&&j < n2)

{

if (array1[i] == array2[j])

{

number++;

i++;

j++;

}

else if (array1[i]>array2[j])

{

j++;

}

else if (array1[i] < array2[j])

{

i++;

}

}

System.out.println("出现相同数的次数为"+number);

}

public static void main(String[] args) {

int a[] = { 0, 1, 2, 3, 4 };

int b[] = { 1, 3, 5, 7, 9 };

Methodfifth m=new Methodfifth();

m. mixed(a, 5, b, 5);

}

法二

public class MethodSixth {

public void mixed(int array1[], int n1, int array2[], int n2)

{

int i = 0, j = 0,number=0;

for(;i

for(;j

{

if (array1[i] == array2[j])

{

number++;

}

}

}

System.out.println("出现相同数的ge数为"+number);

}

}

public static void main(String[] args) {

int a[] = { 0, 1, 2, 3, 4 };

int b[] = { 1, 3, 5, 7, 9 };

Methodfifth m=new Methodfifth();

m. mixed(a, a.length, b, b.length );