Day 14 20190129 老男孩python学习第14天 内容整理

码代码，6个小时。

# 1. 请用代码实现： 利用下划线将列表的每一个元素拼接成字符串， li = ['alex', 'eric', 'rain']
# li = ['alex', 'eric', 'rain']
# print('_'.join(li))# 2. 查找列表中元素，移除每个元素的空格，并查找以a或A开头并且以c结尾的所有元素
#
# li = ["    a  l  e  c   ", "  a r i  c ", "A     l    e   x", "T  o  n  y      ", "   r  a  i  n "]
# li_join = '_'.join(li)
# new_li = li_join.replace(' ', '')
# check_li = new_li.split('_')
#
# for i in check_li:
#     if i.startswith('a') or i.startswith('A') and i.endswith('c'):
#         print(i)# 3. 写代码，有如下列表，按照要求实现每一个功能# li = ['alex', 'eric', 'rain']
# print(len(li))
#
# li.append('seven')
# print(li)
#
# li.insert(0, 'Tony')
# print(li)
#
# li[1] = 'Kelly'
# print(li)# li.remove('eric')
# print(li)
#
# li.pop(1)
# print(li)
#
# del li[2]
# print(li)# del li[1:4]
# print(li)# li.reverse()
# print(li)# for i in range(len(li)):
#     print(i)# for index, i in enumerate(li, start=100):
#     print(index, i)
#
# for i in li:
#     print(i)# 4. 写代码，有如下列表，按照要求实现每一个功能
# li = ['hello', 'seven', ['mon', ['h', 'kelly'], 'all'], 123, 446]
# print(li[2][1][1])
#
# li[2][2] = 'ALL'
# print(li)# 4. 写代码，有如下元组，按照要求实现每一个功能
# tu = ('alex', 'eric', 'rain')# print(len(tu))
# print(tu[1])
# print(tu[0:2])
#
# for i in tu:
#     print(i)# for i in range(len(tu)):
#     print(i)
#
# for index, i in enumerate(tu, start=10):
#     print(index, i)# 6. 有如下变量，请实现要求的功能
# tu = ('alex', [11, 22, {'k1': 'v1', 'k2': ['age', 'name'], 'k3': (11, 22, 33)}, 44])# 元组可存放多个值，元组中的值不可变，但是如果元组里面还有列表、元组、字典等就可变，属于浅不可变# tu[0] = 'ALEX'
# 不可变# 'k2'对应的值是一个列表['age', 'name']，可变
# tu[1][2]['k2'].append('Seven')
# print(tu)# 'k3'对应的值是一个子元组，可变
# tu[1][2]['k3'] = (11, 22, 33, 'Seven')
# print(tu)# 7. 字典
# dic = {'k1': 'v1', 'k2': 'v2', 'k3': [11, 22, 33]}
# for i in dic.keys():
#     print(i)
#
# for i in dic.values():
#     print(i)# for key,value in enumerate(dic):
#     print(key, value)
#
# dic.setdefault('k4', 'v4')
# print(dic)
#
# dic['k1'] = 'alex'
# print(dic)
#
# dic['k3'].append(44)
# print(dic)
#
# dic['k3'].insert(0, 18)
# print(dic)# 8. 转换
# s = 'alex'
# li = [s]
# print(li)
# tu = (s)
# print(tu)
#
# li = ['alex', 'seven']
# tu = (li[0], li[1])
# tu2 = tuple(li)
# print(tu)
# print(tu2)
#
# tu = ('alex', 'seven')
# li = [tu[0], tu[1]]
# li2 = list(tu)
# print(li)
# print(li2)
#
# li = ['alex', 'seven']
# new_dict = {}
# for index, i in enumerate(li, start=10):
#     new_dict[index] = i
#
# print(new_dict)# 9. 元素分类# li = [11, 22, 33, 44, 55, 66, 77, 88, 99, 90]
# dic = {'k1': [], 'k2': []}
# for i in li:
#     if i > 66:
#         dic['k1'].append(i)
#     elif i < 66:
#         dic['k2'].append(i)
#
# print(dic)# 10. 输出商品列表，用户输入序号，显示用户选中的商品
# 商品 li = ["手机"，"电脑"，"鼠标垫"，"游艇"]
# 允许用户添加商品
# 用户输入序号显示内容li = ["手机", "电脑", "鼠标垫", "游艇"]
s = '商品列表'
buy = '购物车商品列表'
shopping_cart = []
exit_flag = Falsewhile not exit_flag:print(s.center(50, '-'))for index, i in enumerate(li, start=0):print('%s. %s' % (index, i))choice = input('请输入您要选择的商品： （按q键买单或者退出）')if choice.isdigit():choice = int(choice)if choice < len(li):print('您选中的商品为：', li[choice])buy_choice = input("，请问是否要添加该商品至您的购物车？（输入'y'添加，否则重新回到商品列表）")if buy_choice == 'y':shopping_cart.append(li[choice])print('商品', li[choice], '已经添加到您的购物车，请继续购物，如需买单请按q键')else:passelse:print('对不起，您输入的商品编号不存在，请重新输入')elif choice == 'q':if len(shopping_cart) == 0:print('感谢您的光临！')exit_flag = Trueelse:print(buy.center(50, '-'))for index, i in enumerate(shopping_cart, start=1):print('%s. %s' % (index, i))exit_flag = Trueelse:print('对不起，请您输入数字编号，谢谢')

　　

c = {'p1': {'c1': ['d1', 'd2', 'd3'], 'c2': ['d4', 'd5', 'd6']},'p2': {'c3': ['d7', 'd8', 'd9'], 'c4': ['d10', 'd11', 'd12']}
}exit_flag = False
p_exit_flag = False
c_exit_flag = False
d_exit_flag = False
t_exit_flag = False
l_exit_flag = Falsewhile not exit_flag:choice = input('请问您是要查看还是修改地域字典，查看请输入r，修改请输入w，退出请输入q：')if choice == 'r':if len(c) > 0:while not p_exit_flag:s_province = '省列表'  # 此处打印省列表print(s_province.center(50, '-'))for i in c.keys():print(i)print(s_province.center(50, '-'))choice_p = input('请问您要查看哪个省的列表？(#号键返回上级菜单)')  # 此处询问客户后续操作while not c_exit_flag:if choice_p in c.keys():s_city = '%s省城市列表' % choice_p  # 此处打印用户选择的省的城市清单print(s_city.center(50, '-'))for i in c[choice_p].keys():print(i)print(s_city.center(50, '-'))choice_c = input('请问您要查看哪个市的列表？(#号键返回上级菜单)')  # 此处询问客户后续操作while not d_exit_flag:if choice_c in c[choice_p].keys():s_district = '%s省%s市列表' % (choice_p, choice_c)  # 此处打印用户选择的省的城市的区清单print(s_district.center(50, '-'))for i in c[choice_p].keys():print(i)print(s_district.center(50, '-'))choice_d = input('请问您要查看哪个区的列表？(#号键返回上级菜单)')  # 此处询问客户后续操作while not t_exit_flag:if choice_d in c[choice_p][choice_c]:s_town = '%s省%s市%s区列表' % (choice_p, choice_c, choice_d)  # 此处打印用户选择的省的城市的区的镇清单print(s_town.center(50, '-'))for i in c[choice_p][choice_c]:print(i)print(s_town.center(50, '-'))choice_d = input('按#号键返回上级菜单，按q键返回至初始菜单')  # 此处询问客户后续操作while not l_exit_flag:if choice_d == '#':l_exit_flag = Trueelif choice_d == 'q':print('返回初始菜单成功！')p_exit_flag = Trueelse:print('输入有误，请重新输入，返回上级菜单请输入#号,按q键返回至初始菜单')elif choice_p == '#':d_exit_flag = Trueelse:print('输入有误，请重新输入，返回上级菜单请输入#号')elif choice_p == '#':c_exit_flag = Trueelse:print('输入有误，请重新输入，返回上级菜单请输入#号')elif choice_p == '#':p_exit_flag = Trueelse:print('输入有误，请重新输入，返回上级菜单请输入#号')else:print('对不起，当前地域字典为空，请先添加后再查看')elif choice == 'w':print()elif choice == 'q':print('退出成功')exit_flag = Trueelse:print('对不起，您输入的操作代码有误，请重新输入')

　　

c = {}exit_flag = False
exit_flag_2 = False
p_exit_flag = False
c_exit_flag = False
d_exit_flag = False
t_exit_flag = False
l_exit_flag = Falsewhile not exit_flag:choice_level_1 = input('欢迎来到国家省市区查询系统，按任意键开始查询，退出请输q：')if choice_level_1 == 'q':print('系统已退出')exit_flag = Trueelse:if len(c) == 0:choice_level_2 = input('对不起，当前查询系统数据为空，请您添加后查询，输入任意字符开始添加，退出请输q: ')if choice_level_2 == 'q':print('系统已退出')exit_flag = Trueelse:while True:province_add = input('请您添加省份名称(q返回初始菜单):  ')if province_add == 'q':breakelse:add_confirm = input('您想要添加的省份名称为：%s，确认请输1，重新输入请输2' % province_add)if add_confirm == '1':if province_add not in c.keys():c[province_add] = {}print('%s添加成功！' % province_add)else:print('对不起，您要添加的省份已经在系统数据中，请勿重复添加，谢谢！')elif add_confirm == '2':continueelse:print('输入有误，请重新输入')