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c语言指针++

Program 1:

程序1：

#include <iostream>
using namespace std;
class Test {
int VAL;
public:
Test(int v)
{
VAL = v;
}
Test* Sum(Test T1, Test T2)
{
VAL = T1.VAL + T2.VAL;
return this;
}
void print()
{
cout << VAL << " ";
}
};
int main()
{
Test T1(10);
Test T2(20);
Test* T3;
T3 = T1.Sum(T1, T2);
T1.print();
T2.print();
T3->print();
return 0;
}

Output:

输出：

30 20 30

Explanation:

说明：

Consider the sum() function, the function is taking two objects of Test class arguments and returning the pointer of the current object using this.

考虑sum()函数，该函数接收Test类参数的两个对象，并使用this返回当前对象的指针。

And, in the main() function, we created two objects T1, T2, and a pointer T3, which is holding the current object pointer returned by sum(). The sum() is adding the values of T1 and T2 and assigning in T1 because we are calling the function sum() using T1 and returning the address of T1 which is assigning to the pointer T3.

并且，在main()函数中，我们创建了两个对象T1 ， T2和一个指针T3 ，该指针保存了sum()返回的当前对象指针。 sum()将T1和T2的值相加并在T1中赋值，因为我们正在使用T1调用函数sum()并返回分配给指针T3的T1地址。

Program 2:

程式2：

#include <iostream>
using namespace std;
class Test {
public:
Test call1()
{
cout << "call1 ";
return *this;
}
Test call2()
{
cout << "call2 ";
return *this;
}
Test call3()
{
cout << "call3 ";
return *this;
}
};
int main()
{
Test T1;
T1.call1().call2().call3();
return 0;
}

Output:

输出：

call1 call2 call3

Explanation:

说明：

Here, we implemented a cascaded function call using this pointer, and created the class Test with 3 member functions call1(), call2(), and call3(). All these functions will return the current object of the class using *this.

在这里，我们使用此指针实现了级联函数调用，并使用3个成员函数 call1() ， call2()和call3()创建了Test类。所有这些函数都将使用* this返回类的当前对象。