将一幅图像取平均值缩小N倍实现方法

        /// <summary>/// 将图像缩小N倍/// </summary>/// <param name="source">原图数据</param>/// <param name="height">原图高度</param>/// <param name="width">原图宽度</param>/// <param name="scale">缩小倍数</param>/// <returns></returns>public static ushort[] ImgNarrow(ushort[] source, int height, int width,int scale){if (Convert.ToBoolean(height % scale) || Convert.ToBoolean(width % scale)){throw new Exception("高宽必须为" + scale + "的倍数");}ushort[] dest = new ushort[height * width / (scale * scale)];int n = 0;for (int y = 0; y < height; y = y + scale){for (int x = 0; x < width; x = x + scale){int index = y * width + x;int sum = 0;for (int i = 0; i < scale; i++){for (int j = 0; j < scale; j++){sum += source[index + i * width + j];}}dest[n] = Convert.ToUInt16(sum / (scale * scale));n++;}}return dest;}

原图是灰度数据，最终的目的是将图像缩小了N倍，然后取周围N*N个点的灰度平均值作为新图像的值，目前这个实现复杂度有点高，有更优解请评论回复