int num = 0x11223344; //4bytechar *str = (char *)&num char *p = (char *)num; //errorcout<<num<<endl;cout<<*str<<endl;      //small-endian（小端字节）的CPU应该输出一个'D', 因为0x44是字母'D'cout<<*str+2<<endl;    //0x44(68) + 2cout<<*(str+2)<<endl;  //character 0x22